limn→∞ 1+24+34+…+n4n5−limn→∞ 13+23+33+…+n3n5, is 

limn1+24+34++n4n5limn13+23+33++n3n5, is 

  1. A

    15

  2. B

    130

  3. C

    0

  4. D

    14

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    Solution:

    we have,

    limn14+24++n4n5limn13+23++n3n5=limnn(n+1)(2n+1)3n2+3n130n5limnn2(n+1)24n5=limn1301+1n2+1n3+3n1n214limn1n1+1n2=6300=15

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