limn→∞ 1n+1+1n+2+…+16n is equal to

limn1n+1+1n+2++16n is equal to

  1. A

    log2

  2. B

     log3

  3. C

    log5 

  4. D

    log6

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    Solution:

    limn1n+1+1n+2++16n=limn1n+1+1n+2++1n+5n=limnr=15n1n+r=limn1nr=15n11+rn

      Lower limit of r=1

     Lower limit of integration =limn1n=0  Upper limit of r=5n  Upper limit of integration =limn5nn=5 from eq(i) 0511+xdx=[log(1+x)]05=log6log1=log6

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