limx→0 1+x+x2−exx2 is equal to

limx01+x+x2exx2 is equal to

  1. A

    1

  2. B

    0

  3. C

    1/2

  4. D

    none of these

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    Solution:

    We have

    limx01+x+x2xxx2=lim_x01+x+x21+x+x22!+x33!+x2=limx0112!x3!x24!+.=112=12

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