limx→0 2log⁡(1+x)−log⁡(1+2x)x2 is equal to

limx02log(1+x)log(1+2x)x2 is equal to

  1. A

    0

  2. B

    1

  3. C

    -1

  4. D

    2

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    Solution:

    limx02log(1+x)log(1+2x)x2

    =limx0log(1+x)21+2xx2=limx0log1+x21+2xx21+2x×11+2x=1

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