limx→0 cos⁡(sin⁡x)−1×2=

limx0cos(sinx)1x2=

  1. A

    1

  2. B

    -1

  3. C

    1/2

  4. D

    -1/2

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    Solution:

    We have,

    limx0cos(sinx)1x2=limx01cos(sinx)sin2x×sin2xx2

    =12×1                 limx01cosxx2=12

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