limx→0 ex+e−x−2×21/x2 is equal to

limx0ex+ex2x21/x2 is equal to

  1. A

    e1/2

  2. B

    e1/4

  3. C

    e1/b

  4. D

    e1/12

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    Solution:

    We have,

    limx0ex+ex2x21x2=limx02x22!+x44!+x66!+x21x2=limx01+2x24!+2x46!+1x2=limx02x24!+2x46!+×1x2=e1/12

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