limx→0 sin⁡πcos2⁡xx2 equals

limx0sinπcos2xx2 equals

  1. A

    π

  2. B

    π

  3. C

    π2

  4. D

    1

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    Solution:

    We have,

    limx0sinπcos2xx2

    =limx0sinππcos2xx2xx2=limx0sinπsin2xπsin2x×πsin2xx2=1×π×(1)2=π

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