limx→1 1+log⁡x−x1−2x+x2 equals

limx11+logxx12x+x2 equals

  1. A

    1

  2. B

    -1

  3. C

    0

  4. D

    none of these

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    Solution:

    We have,

    limx11+logxx12x+x2

                      [By L' Hospital's Rule] 

    =limx11x12(x1)=limx11x2x(x1)=12

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