limx→−1 π−cos−1⁡xx+1 is given by

limx1πcos1xx+1 is given by

  1. A

    1π

  2. B

    12π

  3. C

    1

  4. D

    0

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    Solution:

    Let cos1x=y Then, x1+yπ

     limx1+πcos1xx+1

    =limyππy1+cosy=limyππy2cosy/2

    =limyππy2sinπ2y2×π2y2π2y2

    =limyπ122(π+y)1sinπ2y2π2y2=12π

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