limx→1 ∑r=1n xr−nx−1is equal to 

limx1r=1nxrnx1is equal to 

  1. A

    nx

  2. B

    n(n+1)2

  3. C

    1

  4. D

    0

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    Solution:

    we have, 

    limx1nxnnx=1=limx1x1x1+x212x1+x313x1++xn1nx1=1+2+3++n=n(n+1)2

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