limx→1 sin⁡ex−1−1log⁡x is equal to

limx1sinex11logx is equal to

  1. A

    1

  2. B

    0

  3. C

    e

  4. D

    e1

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    Solution:

    We have,

    limx1sinex11logx=limh0sineh1log(1+h)=limh0sineh1eh1×eh1h×hlog(1+h)=1.

     

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