limx→1 x8−2x+1x4−2x+1 equals - Infinity Learn by Sri Chaitanya

A
3
B
0
C
-3
D
1

Solution:

We have,

$\begin{array}{l} lim_{x \to 1} \frac{x^{8} - 2 x + 1}{x^{4} - 2 x + 1} \\ = lim_{x \to 1} \frac{(x - 1) (x^{7} + x^{6} + x^{5} + x^{4} + x^{3} + x^{2} + x - 1)}{(x - 1) (x^{3} + x^{2} + x - 1)} \\ = lim_{x \to 1} \frac{x^{7} + x^{6} + x^{5} + x^{4} + x^{3} + x^{2} + x - 1}{x^{3} + x^{2} + x - 1} = \frac{6}{2} = 3 \end{array}$

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