limx→πsin3xsin2x is equal to

limxπsin3xsin2x is equal to

  1. A

    32

  2. B

    0

  3. C

    1

  4. D

    -32

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    Solution:

    limxπsin3xsin2x=limu0sin3(π-u)sin2(π-u)(u=x-π)

    =limu0sin3u-sin2u=-32limsin3u3u×2usin2u

    =-32.

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