Number 1, 2, 3, …, 100 are written down on each of the cards A, B and C. One number is selected at random from each of the cards. The probability that the numbers so selected can be the measures (in cm) of three sides of right angled triangles no two of which are similar, is

Number 1, 2, 3, ..., 100 are written down on each of the cards A, B and C. One number is selected at random from each of the cards. The probability that the numbers so selected can be the measures (in cm) of three sides of right angled triangles no two of which are similar, is

  1. A

    41003

  2. B

    3503

  3. C

    361003

  4. D

    None of these

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

    n(S)=100×100×100

    We know that (2n+1)2+2n2+2n2=2n2+2n+12 for all nN

    sides of a right angled triangle whole longest side 100.
    e.g. When n = 1, sides are 3, 4, 5
    and when n = 2, sides are 5, 12, 13 and so on'
    The number of selections of 3, 4, 5 from the three cards by taking one from each is 3!. 

    n(E)=6(3!)

    Hence, P(E)=6(3!)100×100×100=11003502

    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91


      Live ClassesBooksTest SeriesSelf Learning




      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.