(p + 2)th term from the end in the binomial expansion ofx2−2x22n+1 is

(p + 2)th term from the end in the binomial expansion of

x22x22n+1 is

  1. A

     2n+1C2nn(2)2npx2p+12n

  2. B

     2n+1C2nn(2)2npx2n2p

  3. C

     2n+1C2np(2)2npx2n2p+1

  4. D

     2n+1C2np(2)2npx2p1+2n

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    Solution:

    (p + 2)th term from the end

    =[2n+2(p+1)]th=(2np+1)th

    from the beginning 

    and T2np+1=2n+1C2npx22n+1(2np)2x22np

    =2n+1C2np(2)2npx2p+12n

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