∑r=0n (−1)r nCr1+rx1+nx is equal to

r=0n(1)r nCr1+rx1+nx is equal to

  1. A

    1

  2. B

    -1

  3. C

    n

  4. D

    0

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    Solution:

    Let E=r=0n(1)r    nCr1+rx1+nx=11+nxr=0n(1)r nCr(1+rx)=11+nxr=0n(1)rnCr+xr=0nr(1)rnCr=11+nx(0+0)=0nC0nC1+nC2nC3+(1)n  nCn=0

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