### Solution:

Given, red queens and black jacks are removed from a pack of 52 playing cards.We know that a pack of 52 cards contains 12 face cards out of which a pair of king, queen and jacks are red and a pair of king, queen and jacks are black.

So, the total outcomes is $\n \n 52\u22124=48\n $ .

According to the question, the drawn card is a queen.

We know that there are 4 queen cards.

Since, the red queens are removed, the number of favourable outcomes is $\n \n 4\u22122=2\n $ .

Now, the probability of getting a queen card is:

$\n \n \n \n \n \n p=\n \n n(Favorable)\n \n n(Total)\n \n \n \n \n \n \n \n \u21d2p=\n 2\n \n 48\n \n \n \n \n \n \n \n \u21d2p=\n 1\n \n 24\n \n \n \n \n \n \n $

Therefore, the required probability is $\n \n \n 1\n \n 24\n \n \n $ .

Hence, option 2 is correct.