rf n is even, then the middle term in the expansion of x2+1xnis 924 x6, then n is equal to

rf n is even, then the middle term in the expansion of x2+1xnis 924 x6, then n is equal to

  1. A

    10

  2. B

    12

  3. C

    14

  4. D

    None of these

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    Solution:

    Since, n is even, therefore n2+1th term is the middle term.

     Tn2+1=nCn/2x2n/21xn/2=924x6 (given) xn/2=x6n=12

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