rf n is even, then the middle term in the expansion of x2+1xnis 924 x6, then n is equal to

# rf n is even, then the middle term in the expansion of ${\left({\mathrm{x}}^{2}+\frac{1}{\mathrm{x}}\right)}^{\mathrm{n}}$is 924 x6, then n is equal to

1. A

10

2. B

12

3. C

14

4. D

None of these

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### Solution:

Since, n is even, therefore $\left(\frac{\mathrm{n}}{2}+1\right)$th term is the middle term.

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