MathematicsSanjay and Sonia start from a given point and travel by car on a straight road at an average speed of 30 km and 50 km per hour respectively. Sanjay starts at 10 am and Sonia starts 3 hours later. Find the time when Sonia meets Sanjay.

Sanjay and Sonia start from a given point and travel by car on a straight road at an average speed of 30 km and 50 km per hour respectively. Sanjay starts at 10 am and Sonia starts 3 hours later. Find the time when Sonia meets Sanjay.


  1. A
    5:30 p.m
  2. B
    7:30 p.m
  3. C
    2:30 p.m
  4. D
    4:30 p.m 

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    Solution:

    It is given the average speeds of 30 km and 50 km per hour of Sanjay and Sonia respectively.
    Let the time taken for which Sanjay to cover a distance be x hours.
    Sonia starts 3 hours later than Sanjay.
    Time taken for Sonia to drive a car to cover a distance will be ‘x – 3’ hours
    Given that the two cars start from the same point and they will meet again when they have covered equal distances.
    Distance covered by Sonia = Distance covered by Sonia
    30x = 50(x – 3)
    30x = 50x – 150
    20x = 150
    x = 7.5
    i.e, time taken by Sanjay to cover the distance is 7 hours and 30 minutes
    Thus, the time when Sonia meets Sanjay will be at 10:00 hours + 7:30 hours = 17:30 hours or 5:30 p.m
    Hence, the required time is 5:30 p.m.
    Therefore, 1 is the correct option.
     
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