MathematicsSec 15π4=

$Sec 15 \frac{π}{4} =$

A
$\frac{1}{\sqrt{2}}$
B
$- \frac{1}{\sqrt{2}}$
C
$\sqrt{2}$
D
$- \sqrt{2}$

Solution:

The given value is $S e c (\frac{15 π}{4})$

Using formula $S e c (n \cdot 2 π + θ) = S e c θ$ , rewrite the above value as below.

$\begin{array}{rcl} S e c (\frac{15 π}{4}) & = & S e c (2 (2 π) + \frac{π}{4}) \\ = & S e c (\frac{π}{4}) \\ = & \sqrt{2} \end{array}$

Therefore, $S e c (\frac{15 π}{4}) = \sqrt{2}$

Related content

Area of Square

Area of Isosceles Triangle

Pythagoras Theorem

Triangle Formulae

Perimeter of Triangle Formula

Area Formulae

Volume of Cone Formula

Matrices and Determinants_mathematics

Critical Points Solved Examples

Type of relations_mathematics