MathematicsShanti sweets stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of the dimensions 25cm × 20 cm × 5 cm and the smaller of dimensions 15cm × 12cm × 5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs.4 for 1000 cm2, find the cost of the cardboard required for supplying 250 boxes of each kind.

Shanti sweets stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of the dimensions 25cm × 20 cm × 5 cm and the smaller of dimensions 15cm × 12cm × 5cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs.4 for 1000 cm2, find the cost of the cardboard required for supplying 250 boxes of each kind.


  1. A
    Rs 1092
  2. B
    Rs 2184
  3. C
    Rs 2114
  4. D
    Rs 1184 

    Fill Out the Form for Expert Academic Guidance!l



    +91



    Live ClassesBooksTest SeriesSelf Learning



    Verify OTP Code (required)

    I agree to the terms and conditions and privacy policy.

    Solution:

     Given: Length of big box (l) = 25 cm
    Breadth of big box (b) = 20 cm
    Height of the big box (h) = 5 cm
    We know that,
    Total surface area of cuboid = 2(lb+bh+hl)
    Total surface area of bigger box = 2(25×20+20×5+5×25)
    =2(500+100+125)
     =2(725)
    =1450 cm2
    Now, 5% is required for overlapping i.e., 5% of 1450 = 5100×1450=72.5 cm2
    Now, Length of small box(L) = 15cm
    Breadth of small box (B) = 12 cm
    Height of the small box (H) = 5 cm
    We know that,
    Total surface area of cuboid = 2(lb+bh+hl)
    Total surface area of smaller box = 2(15×12+12×5+5×15)
     =2(180+60+75)
     =2(315)
    = 630 cm2
    Now, 5% is required for overlapping i.e., 5% of 630 = 5100×630=31.5 cm2
    Thus, the total surface area of both the boxes = 1450 cm2 + 72.5 cm2 + 630 cm2 + 31.5 cm2
     =2184 cm2
    Now, total surface area of 250 such boxes =250×2184=546,000 cm2
    Since, the cost of 1000 cm2 = Rs 4
    Cost of 546,000 cm2 = Rs 4 ×546=Rs 2184
    Hence, 2 is the correct option.
     
    Chat on WhatsApp Call Infinity Learn

      Talk to our academic expert!



      +91


      Live ClassesBooksTest SeriesSelf Learning




      Verify OTP Code (required)

      I agree to the terms and conditions and privacy policy.