Simplify the following expression and find the product when x = -2 and y = -1. 2xy2-x2y23x+y-4xy - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

(2 xy² - x²y²) (3 x + y - 4 xy) .

So, (2 xy² - x²y²) (3 x + y - 4 xy)

can be written as

2 xy² (3 x + y - 4 xy) - x²y² (3 x + y - 4 xy) .

6 x 2 y 2 + 2 xy 3 - 8 x 2 y 3 - 3 x 3 y 2 - x 2 y 3 + 4 x 3 y 3

= 6 x²y² + 2 xy³ - 9 x²y³ - 3 x³y³ + 4 x³y³

(2 xy² - x²y²) (3 x + y - 4 xy)

6 x²y² + 2 xy³ - 9 x²y³ - 3 x³y² + 4 x³y³

Now, we need to find the value of the product when x = - 2 and y = - 1

To find the value of the product, we will substitute

x = - 2 andy = - 1

in 6 x²y² + 2 xy³ - 9 x²y³ - 3 x³y² + 4 x³y³

On substituting x = - 2 and y = - 1

in 6 x²y² + 2 xy³ - 9 x²y³ - 3 x³y² + 4 x³y³

We get :

6 (- 2) ² (- 1) ² + 2 (- 2) (- 1) ³ - 9 (- 2) ² (- 1) ³ - 3 (- 2) ³ (- 1) ² + 4 (- 2) ³ (- 1) ³ .

Now, we know (- 1) ² = 1, (- 1) ³ = - 1, (- 2) ² = 4 and (- 2) ³ = - 8 .

So, the value of the product will be equal to

(6 \times 4 \times 1) + (2 \times (- 2) \times (- 1)) - (9 \times 4 \times (- 1)) - (3 \times (- 8) \times 1) + (4 \times (- 8) \times (- 1)) .

= 24 + 4 + 36 + 24 + 32

= 120

Hence, the value of (2 xy² - x²y²) (3 x + y - 4 xy) when x = - 2 and y = - 1 is 120 .

Simplify the following expression and find the product when x = -2 and y = -1. $(2 x y^{2} - x^{2} y^{2}) (3 x + y - 4 xy)$