∫sin⁡x+cos⁡xsin⁡(x−α)dx is equal to

sinx+cosxsin(xα)dx is equal to

  1. A

    (cosαsinα)(xα)+(cosα+sinα)log|sin(xα)|+C

  2. B

    (cosα+sinα)(xα)+(cosαsinα)log|sin(xα)|+C

  3. C

    (cosα+sinα)(x+α)+(cosαsinα)log|sin(x+α)|+C

  4. D

    none of these

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    Solution:

    We have,

    sinx+cosxsin(xα)dx

    =sin(t+α)+cos(t+α)sintdt, Where t=xα

    =(cosα+sinαcott+cosαcottsinα)dt=(cosαsinα)t+(sinα+cosα)log|sint|+C=(cosαsinα)(xα)+(cosα+sinα)log|sin(xα)|+C

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