Six coins are tossed simultaneously. The probability of getting atleast 4 heads is

Six coins are tossed simultaneously. The probability of getting atleast 4 heads is

A
$\frac{11}{64}$
B
$\frac{11}{32}$
C
$\frac{15}{44}$
D
$\frac{21}{32}$

Solution:

$P (X = 4) + P (X = 5) + P (X = 6)$

= $[{}^{6}C_{4} + {}^{6}C_{5} + {}^{6}C_{6}] {(\frac{1}{2})}^{6}$

$= \frac{11}{32}$

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