Solution:
It is given that, a data of marks obtained by students.
By constructing the frequency distribution table for
students who have scored marks more than or equal to
.Find the frequency by subtracting the cumulative frequency from the preceding one from backwards.
Consider the class interval 80 – 90, the cumulative frequency is 4.
And so the frequency is 4.
Consider the class interval 70 -80, the cumulative frequency is 6.
And so the frequency is 6 - 4 = 2.
Consider the class interval 60 - 70, the cumulative frequency is 11.
And so the frequency is 11 - 6 = 5.
Consider the class interval 50 - 60, the cumulative frequency is 17.
And so the frequency is 17 - 11 = 6.
Consider the class interval 40 - 50, the cumulative frequency is 23.
And so the frequency is 23 - 17 = 6.
Consider the class interval 30 - 40, the cumulative frequency is 27.
And so the frequency is 27 - 23 = 4.
Consider the class interval 20 -30, the cumulative frequency is 30.
And so the frequency is 30 - 27 = 3.
Consider the class interval; 10 -20, the cumulative frequency is 32.
And so the frequency is 32 – 30 = 2.
Consider the class interval; 0 - 10, the cumulative frequency is 34.
And so the frequency is 34 - 32 = 2.
The table is given by,
Hence, the given table is true.Hence, option 1 is correct.
