Solution:The given statement is true.
Concept- We solve this problem by applying the ⁷concept of congruent triangles to obtain the necessary condition, i.e., to prove the perpendicular bisector.
Here, is equidistant from points and .
and is equidistant from points and We have to prove that and In and (1)
..... (SSS congruence rule)
Hence, ....... (C.P.C.T) ….(3)
In (SAS congruence rule)
As is a line segment,
Hence, and is bisector of .
Hence, the given statement is true.