Solution:
We have two linear equations with two variables in it.a(b-5) = ab-5a -----(1)
b(5-a)= 5b-ab -----(2)
Subtract eq (1) from eq (2), we get
= (5b-ab) – (ab-5a)
= 5b-ab-ab+5a (-ab-ab=-2ab)
= 5a+5b-2ab
So, option 2 is correct.
MathematicsSubtract a(b-5) from b(5-a)
Subtract a(b-5) from b(5-a)
a(b-5) = ab-5a -----(1)
b(5-a)= 5b-ab -----(2)
Subtract eq (1) from eq (2), we get
= (5b-ab) – (ab-5a)
= 5b-ab-ab+5a (-ab-ab=-2ab)
= 5a+5b-2ab
So, option 2 is correct.
