Solution:
Let the side of the first square be a.Let the side of Second Square be b.
Area of 1st square= a2
Area of 2nd square= b2
Perimeter of 1st square= 4a
Perimeter of 2nd square= 4b
Difference of perimeters of the square is 24m.
4a-4b=24
4(a-b) =24
a - b= 6 --------- (1)
Sum of the areas of the square is 468m2.
------------ (2)From eq (1), we write a as
a=b+6 ------------ (3)
Put the value of a in the (2) equation.
Side of the square is never negative. So we consider b=12.Put the value of b in eq (3).
We get, a=18 and b=12
So, the two sides of the square are 18m and 12m.
Hence, Option (3) is the correct Ans:.
