Suppose A, B are two 3×3 matrices such that A–1 exists. Then  (A−B)A−1(A+B) is equal to 

Suppose A, B are two 3×3 matrices such that A–1 exists. Then  (AB)A1(A+B) is equal to 

  1. A

    (A+B)A1(AB)

  2. B

    A1B+B2

  3. C

    IBAB1(AB)

  4. D

    I+BAB1(A+B)

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    Solution:

    (AB)A1(A+B)=IBA1(A+B)=A+BBA1ABA1B=ABA1B=A+BBA1ABA1B=(A+B)BA1(A+B)=(A+B)IBA1=(A+B)A1(AB)

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