Suppose p ∈ R. If the fourth term in the expansion of px+1xn is 52 then (n, p) is equal to:

Suppose p  R. If the fourth term in the expansion of px+1xn is 52 then (n, p) is equal to:

  1. A

    (5, 1/2) 

  2. B

    (6, 1/2)

  3. C

    (8, 1/2) 

  4. D

    (10, 1/2)

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    Solution:

    T4=nC3(px)n31x3=nC3pn3xn6=52n6=0 and 6C3p3=52n=6,p=1/2

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