tan230°+4sin245°+13cos230°=  

tan230°+4sin245°+13cos230°=  

  1. A
    2712
  2. B
    1512
  3. C
    2512
  4. D
    1512

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    Solution:

    tan230°+4sin245°+13cos230°=

    =(13)2+4.(12)2+13(32)2

    =13+4.12+13.34

    =13+14+2

    =4+3+2412

    =3112

    =2712

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