tan⁡cot−1⁡x is equal to

$\tan (\cot^{- 1} x)$ is equal to

A
$\frac{π}{2} - x$
B
$\cot (\tan^{- 1} x)$
C
$\tan x$
D
none of these

Solution:

We have,

$\tan (\cot^{- 1} x) = \tan (\frac{π}{2} - \tan^{- 1} x) = \cot (\tan^{- 1} x)$

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