∫{tan⁡x+cot⁡x}dx is equal to 

{tanx+cotx}dx is equal to 

  1. A

    sin1(sinxcosx)+C

  2. B

    2sin1(sinxcosx)+C

  3. C

    2cos1(sinxcosx)+C

  4. D

    none of these

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    Solution:

    We have,

    I={tanx+cotx}dx=sinx+cosxsinxcosxdx I=2sinx+cosx2sinxcosxdx I=211(sinxcosx)2d(cosx+sinx) I=2sin1(sinxcosx)+C.

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