Search for: The AM of 2n+1C0,2n+1C1,2n+1C2,…,2n+1Cn is The AM of 2n+1C0,2n+1C1,2n+1C2,…,2n+1Cn is A2nnB2nn+1C22nnD22n(n+1) Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution: 2n+1C0+2n+1C1+2n+1C2+…+2n+1C2n+2n+1C2n+1=22n+1Now 2n+1C0=2n+1C2n+1, 2n+1C1=2n+1C2n…2n+1Cr=2n+1C2n−r+1So, sum of first (n + 1 ) terms= sum of last (n + 1 ) terms⇒ 2n+1C0+2n+1C1+2n+1C2+…+2n+1Cn=22n⇒ 2n+1C0+2n+1C1+2n+1C2+…+2n+1Cnn+1=22n(n+1) Related content Oppositional Defiant Disorders Good Friday Wishes CBSE Class 9 Physics Motion Worksheet Autism Spectrum Disorder Sine and Cosine Waves Hindu Festivals List 2024 JEE Main Eligibility Criteria 2024 Session 2 (Released), Age Limits, Qualifying Marks, and Important Factor MCQs on Plant Hormones Class 10 5 Reasons To Choose The Commerce Stream After 10th Fl Words