The arithmetic mean of  nC0,nC1,…,nCn, is

The arithmetic mean of  nC0,nC1,,nCn, is

  1. A

    1n

  2. B

    2nn

  3. C

    2n1n

  4. D

    2n+1n

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    Solution:

    Clearly, Required mean = nC0+nC1++nCnn=2nn

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