The circumference of a circle is measured as 56 cm with an error 0.02 cm, The percentage error in its area, is

# The circumference of a circle is measured as 56 cm with an error 0.02 cm, The percentage error in its area, is

1. A

$\frac{1}{7}$

2. B

$\frac{1}{28}$

3. C

$\frac{1}{14}$

4. D

$\frac{1}{56}$

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### Solution:

Let $r$ be the radius, $C$ be the circumference and $A$

be the area of the circle. Then,

and $\mathrm{\Delta }A=\frac{dA}{dr}\mathrm{\Delta }r$

We have,

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