The co-ordinates of the point in which the line joining the points (3, 5, -7) and -2, 1, 8 is intersected by the plane yz are given by

The co-ordinates of the point in which the line joining the points $(3, 5, - 7)$ and $(- 2, 1, 8)$ is intersected by the plane $yz$ are given by

A
$(0, \frac{13}{5}, 2)$
B
$(0, - \frac{13}{5}, - 2)$
C
$(0, - \frac{13}{5}, \frac{2}{5})$
D
$(0, \frac{13}{5}, \frac{2}{5})$

Solution:

Ratio $= - (\frac{3}{- 2}) = \frac{3}{2} [By yz plane = - (\frac{x_{1}}{x_{2}})]$

$∴$ Required co-ordinates of the points are,

$[\frac{6 - 6}{5}, \frac{10 + 3}{5}, \frac{- 14 + 24}{5}] = (0, \frac{13}{5}, 2) .$

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