Solution:
Let AD = x cm and diagonal BD = 3x cm.
In right-angled triangle DAB,
AD2 + AB2 = BD2 (Using Pythagoras Theorem)
x2 + AB2 = (3x)2
⇒ x2 + AB2 = 9x2
⇒ AB2 = 9x2 – x2
⇒ AB2 = 8x2
⇒ AB = √8x = 2√2x
Required ratio of AB : AD = 2√2x : x = 2√2 : 1
The diagonal of a rectangle is thrice its smaller side. Find the ratio of its sides.
The diagonal of a rectangle is thrice its smaller side. Find the ratio of its sides.
