The distance between (2, -3) and (10, y) is 10, then y = ? - Sri Chaitanya Infinity Learn Best Online Courses for NCERT Solutions, CBSE, ICSE, JEE, NEET, Olympiad and Class 6 to 12

(2, -3) $\bar{< - - - - 10 - - - - >}$ (10, 4)

PQ = $\sqrt{{(10 - 2)}^{2} + {(y - 3)}^{2}}$ = $\sqrt{{(8)}^{2} + {(y + 3)}^{2}}$

Since PQ=10

$\sqrt{{(8)}^{2} + {(y + 3)}^{2}} = 10$

Simplify the above equation and find the value of y.

Squaring both sides

64+(y+3)²=100

(y+3)²=36

$y + 3 = \pm 6$

y+3=+6 or y+3=-6

therefore, y= 3 or -9

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