The distance travelled by a motor car in t seconds after the brakes are applied is s feet, where s=22t−12t2 The distance travelled by the car before it stops, is 

The distance travelled by a motor car in t seconds after the brakes are applied is s feet, where s=22t12t2 The distance travelled by the 

car before it stops, is 

  1. A

    10.08 ft

  2. B

     10 ft

  3. C

    11 ft

  4. D

     11.5 ft 

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    Solution:

    We have,

    s=22t12t2dsdt=2224t

    When the car stops, dsdt=0

     2224t=0t=1122 s=22t12t2s=22×112212×11222=10.08ft.

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