The distance travelled by a motor car in t seconds after the brakes are applied is s feet, where s=22t−12t2 The distance travelled by the car before it stops, is

# The distance travelled by a motor car in $t$ seconds after the brakes are applied is feet, where $s=22t-12{t}^{2}$ The distance travelled by the car before it stops, is

1. A

2. B

3. C

4. D

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### Solution:

We have,

$s=22t-12{t}^{2}⇒\frac{ds}{dt}=22-24t$

When the car stops, $\frac{ds}{dt}=0$

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