The equation 3sin2⁡x+10cos⁡x−6=0 is satisfied, if

A
$x = nπ \pm \cos^{- 1} (\frac{1}{3})$
B
$x = 2 nπ \pm \cos^{- 1} (\frac{1}{3})$
C
$x = nπ \pm \cos^{- 1} (\frac{1}{6})$
D
$x = 2 nπ \pm \cos^{- 1} (\frac{1}{6})$

Solution:

We have, $3 \sin^{2} x + 10 \cos x - 6 = 0$

$\begin{array}{ll} \Rightarrow (\cos x - 3) (3 \cos x - 1) = 0 \\ \Rightarrow \cos x \neq 3 or \cos x = \frac{1}{3} \\ \Rightarrow x = 2 nπ \pm \cos^{- 1} (\frac{1}{3}) \end{array}$

The equation $3 \sin^{2} x + 10 \cos x - 6 = 0$ is satisfied, if

Solution:

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