Solution:
Let y = mx be a chord.
Then the points of intersections are given by
Since (0, 0) divides chord in the ratio 1 : 4, we have
Therefore, the lines are y= 0 and 7y + 24 x = 0.
The equation of the chord of the circle which passes through the origin such that the origin divides it in the ratio 4 : 1, is
Let y = mx be a chord.
Then the points of intersections are given by
Since (0, 0) divides chord in the ratio 1 : 4, we have
Therefore, the lines are y= 0 and 7y + 24 x = 0.