Solution:
We know f(x)=[x] is discontinuous at integral values of x.Then, f(x)=[sinx] will be discontinuous where sinx will be integer.
Thus the solution set is, sinx=0,±1⇒x=nπ,(2n+1), where n∈I
Hence 1 is the correct option.
The function f(x)=[sinx] is not continuous at ([x] is the greatest integer less than or equal to x)