The general solution of :sin2⁡θsec⁡θ+3tan⁡θ=0 is 

The general solution of :sin2θsecθ+3tanθ=0 is 

  1. A

    θ=nπ+(1)n+1π3, θ=nπ

  2. B

    θ=nπ

  3. C

    θ=nπ+(1)n+1π3

  4. D

    θ=nπ2

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    Solution:

    The given equation can be written as 

    (sinθ+3)tanθ=0tanθ=0θ=nπ, nZ

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