The last term in the binomial expansion of 2−12n is  1(3)913log⁡38, then the 5th term from the beginning is

The last term in the binomial expansion of 212n is  1(3)913log38, then the 5th term from the beginning is

  1. A

     10C6

  2. B

    2 10C4

  3. C

    12 10C4

  4. D

    10C6

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    Solution:

     5th term from the beginning

    =10C4(2)104124=2 10C4

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