The last term in the binomial expansion of 2−12n is 1(3)913log⁡38, then the 5th term from the beginning is

The last term in the binomial expansion of ${(\sqrt{2} - \frac{1}{\sqrt{2}})}^{n}$ is ${(\frac{1}{(3) 9^{\frac{1}{3}}})}^{\log 3^{8}}$ , then the $5^{t h}$ term from the beginning is

$∴$ 5th term from the beginning

$=^{10} C_{4} (\sqrt{2})^{10 - 4} {(- \frac{1}{\sqrt{2}})}^{4} = 2 (^{10} C_{4})$

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