MathematicsThe maximum area of the rectangle whose sides pass through the vertices of a given rectangle of sides a and b is

The maximum area of the rectangle whose sides pass through the vertices of a given rectangle of sides a and b is

  1. A

    2(ab)

  2. B

    12(a+b)2

  3. C

    12(a2+b2)

  4. D

    12(a2b2)

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    Solution:

    Area,  A=(asinθ+bcosθ)(acosθ+bsinθ)

    =ab+(a2+b2)2sin2θ

    A is maximum when sin 2θ  is maximum.

    Therefore,  Amax=ab+(a2+b2)2=12(a+b)2

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