Search for: MathematicsThe maximum area of the rectangle whose sides pass through the vertices of a given rectangle of sides a and b is The maximum area of the rectangle whose sides pass through the vertices of a given rectangle of sides a and b is A2(ab)B12(a+b)2C12(a2+b2)D12(a2−b2) Fill Out the Form for Expert Academic Guidance!l Grade ---Class 1Class 2Class 3Class 4Class 5Class 6Class 7Class 8Class 9Class 10Class 11Class 12 Target Exam JEENEETCBSE +91 Preferred time slot for the call ---9 am10 am11 am12 pm1 pm2 pm3 pm4 pm5 pm6 pm7 pm8pm9 pm10pm Please indicate your interest Live ClassesBooksTest SeriesSelf Learning Language ---EnglishHindiMarathiTamilTeluguMalayalam Are you a Sri Chaitanya student? NoYes Verify OTP Code (required) I agree to the terms and conditions and privacy policy. Solution:Area, A=(asinθ+bcosθ)(acosθ+bsinθ)=ab+(a2+b2)2sin2θA is maximum when sin 2θ is maximum.Therefore, Amax=ab+(a2+b2)2=12(a+b)2 Related content Area of Square Area of Isosceles Triangle Pythagoras Theorem Triangle Formula Perimeter of Triangle Formula Area Formulae Volume of Cone Formula Matrices and Determinants_mathematics Critical Points Solved Examples Type of relations_mathematics