The mean deviation (approximately) from the mode for the data, is 20, 25, 30, 18, 15, 40

# The mean deviation (approximately) from the mode for the data, is 20, 25, 30, 18, 15, 40

1. A

6.71

2. B

4.52

3. C

7.61

4. D

5.33

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### Solution:

We have,

Mean $=\frac{20+25+30+18+15+40}{6}=\frac{148}{6}$

Median $=\frac{20+25}{2}=\frac{45}{2}$

$\therefore$ Mode = 3 Median -2 Mean $=\frac{135}{2}-\frac{148}{3}=\frac{109}{6}$

Hence, mean deviation about mode is given by

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