The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean, is

The mean deviation of the numbers $3, 4, 5, 6, 7$ from the mean, is

A
$25$
B
5
C
$1.2$
D
$0$

Solution:

We have,

$\bar{X} = \frac{3 + 4 + 5 + 6 + 7}{5} = 5$

$∴$ Mean deviation from the mean

$\begin{array}{l} = \frac{| 3 - 5 | + | 4 - 5 | + | 5 - 5 | + | 6 - 5 | + | 7 - 5 |}{5} \\ = \frac{2 + 1 + 0 + 1 + 2}{5} = 1.2 \end{array}$

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