The median from the following distribution  Class: 5−1010−1515−2020−2525−3030−3535−4040−45 Frequency: 5615105422

The median from the following distribution 

 Class: 5101015152020252530303535404045 Frequency: 5615105422

  1. A

    19

  2. B

    19.5

  3. C

    20

  4. D

    18

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    Solution:

    First we prepare the following table to compute the median

    ClassFrequencyCumulative Frequency

    5-10

    10-15

    15-20

    20-25

    25-30

    30-35

    35-40

    40-45

    5

    6

    15

    10

    5

    4

    2

    2

     

    5

    11

    26

    36

    41

    45

    47

    49

     

     N=49 

    We have N=49

    N2=492=24.5

    The cumulative frequency just greater than N /2 is 26 and the corresponding class is 15-20. Thus 15-20 is the median class such that 

    l=15,f=15,F=11,h=5.

      Median =l+N2Ff×h  Median =15+24.51115×5=15+13.53=19.5

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