The number of distinct terms in the expansion of (1+3x+3×2+x37 is

The number of distinct terms in the expansion of (1+3x+3x2+x37 is

  1. A
  2. B
  3. C
  4. D

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    Solution:

    1+3x+3x2+x37=(1+x)37=(1+x)21

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